4(m+4^2)-4*m^2+20=276

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Solution for 4(m+4^2)-4*m^2+20=276 equation: 



4(m+4^2)-4m^2+20=276

We move all terms to the left:

4(m+4^2)-4m^2+20-(276)=0

We add all the numbers together, and all the variables

-4m^2+4(m+4^2)-256=0

We multiply parentheses

-4m^2+4m+64-256=0

We add all the numbers together, and all the variables

-4m^2+4m-192=0

a = -4; b = 4; c = -192;
Δ = b2-4ac
Δ = 42-4·(-4)·(-192)
Δ = -3056
Delta is less than zero, so there is no solution for the equation

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